In expansion of {left( {3x - frac{1}{{{x^2}}}} right)^{10}} then 5^{th} term from end is :-

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7.Binomial Theorem

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In the expansion of ${\left( {3x - \frac{1}{{{x^2}}}} \right)^{10}}$ then $5^{th}$ term from the end is :-

$\frac{{17010}}{{{x^6}}}$

$\frac{{17010}}{{{x^9}}}$

$\frac{{17010}}{{{x^8}}}$

$\frac{{17010}}{{{x^{-1}}}}$

Solution

$\left(-\frac{1}{x^{2}}+3 x\right)^{10}$

${{\rm{T}}_5}({\rm{E}}) = {\,^{10}}{{\rm{C}}_4}{\left( { – \frac{1}{{{{\rm{x}}^2}}}} \right)^6} \times {(3{\rm{x}})^4} = \frac{{17010}}{{{{\rm{x}}^8}}}$

Standard 11

Mathematics

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(AIEEE-2002)

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(JEE MAIN-2021)

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In the expansion of ${\left( {3x - \frac{1}{{{x^2}}}} \right)^{10}}$ then $5^{th}$ term from the end is :-

Solution

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